python merge dictionaries
dict1 = {'color': 'blue', 'shape': 'square'}
dict2 = {'color': 'red', 'edges': 4}
dict1.update(dict2) #if a key exists in both, it takes the value of the second dict
# dict1 = {'color': 'red', 'shape': 'square', 'edges': 4}
# dict2 is left unchangedpython merge dictionaries
# Python >= 3.5:
def merge_dictionaries(a, b):
return {**a, **b}
# else:
def merge_dictionaries(a, b):
c = a.copy() # make a copy of a
c.update(b) # modify keys and values of a with the b ones
return c
a = { 'x': 1, 'y': 2}
b = { 'y': 3, 'z': 4}
print(merge_dictionaries(a, b)) # {'y': 3, 'x': 1, 'z': 4}merge dicts python
z = x | y # NOTE: 3.9+ ONLY
z = {**x, **y} # NOTE: 3.5+ ONLYpython merge dictionaries
def merge_dicts(dict1, dict2):
"""Here's an example of a for-loop being used abusively."""
return {**dict2, **{k: (v if not (k in dict2) else (v + dict2.get(k)) if isinstance(v, list) else merge_dicts(v, dict2.get(k))) if isinstance(v, dict) else v for k, v in dict1.items()}}convert two lists to a single dictionary python
#initialize lists
key_list = ['red', 'green', 'blue']
value_list = [1, 2, 3]
#convert lists
my_dict = {}
for key in key_list:
for value in value_list:
my_dict[key] = value
value_list.remove(value)
break
print(my_dict)merged all dictionaries in a list python
>>> result = {}
>>> for d in L:
... result.update(d)
...
>>> result
{'a':1,'c':1,'b':2,'d':2}Copyright © 2021 Codeinu
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