number of trailing zeros in factorial python
def findTrailingZeros(n):
# Initialize result
count = 0
# Keep dividing n by
# 5 & update Count
while(n >= 5):
n //= 5
count += n
return count
# Driver program
n = 100
print("Count of trailing 0s " +
"in 100! is", findTrailingZeros(n))Copyright © 2021 Codeinu
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