number of trailing zeros in factorial python
def findTrailingZeros(n):
 
    # Initialize result
    count = 0
 
    # Keep dividing n by
    # 5 & update Count
    while(n >= 5):
        n //= 5
        count += n
 
    return count
 
 
# Driver program
n = 100
print("Count of trailing 0s " +
      "in 100! is", findTrailingZeros(n))
