how can I sort a dictionary in python according to its values?
s = {1: 1, 7: 2, 4: 2, 3: 1, 8: 1}
k = dict(sorted(s.items(),key=lambda x:x[0],reverse = True))
print(k)how can I sort a dictionary in python according to its values?
s = {1: 1, 7: 2, 4: 2, 3: 1, 8: 1}
k = dict(sorted(s.items(),key=lambda x:x[0],reverse = True))
print(k)python sort dictionary by key
def sort_dict(dictionary, rev = True):
l = list(dictionary.items())
l.sort(reverse = rev)
a = [item[1] for item in l]
z = ''
for x in a:
z = z + str(x)
return(z)Copyright © 2021 Codeinu
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