how can I sort a dictionary in python according to its values?
s = {1: 1, 7: 2, 4: 2, 3: 1, 8: 1}
k = dict(sorted(s.items(),key=lambda x:x[0],reverse = True))
print(k)how can I sort a dictionary in python according to its values?
s = {1: 1, 7: 2, 4: 2, 3: 1, 8: 1}
k = dict(sorted(s.items(),key=lambda x:x[0],reverse = True))
print(k)python sort the values in a dictionaryi
from operator import itemgetter
new_dict = sorted(data.items(), key=itemgetter(1))python sort dictionary by key
In [1]: import collections
In [2]: d = {2:3, 1:89, 4:5, 3:0}
In [3]: od = collections.OrderedDict(sorted(d.items()))
In [4]: od
Out[4]: OrderedDict([(1, 89), (2, 3), (3, 0), (4, 5)])sort dictionary by key
dictionary_items = a_dictionary.items()
sorted_items = sorted(dictionary_items)sorting-a-dictionary-by-value-then-by-key
[(14,2), (12,2), (9,1)] # output from print
[(90,4), (99,3), (101,1), (100,1), (92,1)]Copyright © 2021 Codeinu
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