how can I sort a dictionary in python according to its values?
s = {1: 1, 7: 2, 4: 2, 3: 1, 8: 1}
k = dict(sorted(s.items(),key=lambda x:x[0],reverse = True))
print(k)how can I sort a dictionary in python according to its values?
s = {1: 1, 7: 2, 4: 2, 3: 1, 8: 1}
k = dict(sorted(s.items(),key=lambda x:x[0],reverse = True))
print(k)how to sort a dictionary py
orders = {
'cappuccino': 54,
'latte': 56,
'espresso': 72,
'americano': 48,
'cortado': 41
}
sort_orders = sorted(orders.items(), key=lambda x: x[1], reverse=True)
for i in sort_orders:
print(i[0], i[1])Copyright © 2021 Codeinu
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