Answers for "sort a dictionary based on a list"

sort list of dictionaries by key python

newlist = sorted(list_to_be_sorted, key=lambda k: k['name'])

Posted by: Guest on March-25-2020

sorting a dictionary in python

x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
{k: v for k, v in sorted(x.items(), key=lambda item: item[1])}
{0: 0, 2: 1, 1: 2, 4: 3, 3: 4}

Posted by: Guest on April-22-2020

Code answers related to "sort a dictionary based on a list"