how can I sort a dictionary in python according to its values?
s = {1: 1, 7: 2, 4: 2, 3: 1, 8: 1}
k = dict(sorted(s.items(),key=lambda x:x[0],reverse = True))
print(k)how can I sort a dictionary in python according to its values?
s = {1: 1, 7: 2, 4: 2, 3: 1, 8: 1}
k = dict(sorted(s.items(),key=lambda x:x[0],reverse = True))
print(k)python get dictionary keys sorted by value
sorted(A, key=A.get)sort the dictionary in python
d = {2: 3, 1: 89, 4: 5, 3: 0}
od = sorted(d.items())
print(od)sort a dictionary
from operator import itemgetter
new_dict = sorted(data.items(), key=itemgetter(1))python sort dict by value
A={1:2, -1:4, 4:-20}
{k:A[k] for k in sorted(A, key=A.get)}
output:
{4: -20, 1: 2, -1: 4}sort dictionary by key
dictionary_items = a_dictionary.items()
sorted_items = sorted(dictionary_items)Copyright © 2021 Codeinu
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