Answers for "sorted_values = sorted(dictionary.items(), key=lambda x: x[1], reverse=True)[0:numberof_values]"

how can I sort a dictionary in python according to its values?

s = {1: 1, 7: 2, 4: 2, 3: 1, 8: 1}
k = dict(sorted(s.items(),key=lambda x:x[0],reverse = True))
print(k)

Posted by: Guest on November-23-2020

Code answers related to "sorted_values = sorted(dictionary.items(), key=lambda x: x[1], reverse=True)[0:numberof_values]"