Answers for "python give error once"

error handling Pyhtin

# taking input from the user 
try:
    age = int(input("Please enter your age: "))
    print(age)
except:
    print("please enter a number instead! ")
    print('bye')


# if you wanna ask their age until they enter the correct number use While Loop
while True:
    try:
        age = int(input("Please enter your age: "))
        print(age)
    except:
        print("please enter a number instead! ")
    else:
        break

catch error data with except python

import sys
try:
	S = 1/0 #Create Error
except: # catch *all* exceptions
    e = sys.exc_info()
    print(e) # (Exception Type, Exception Value, TraceBack)

############
#    OR    #
############
try:
	S = 1/0
except ZeroDivisionError as e:
    print(e) # ZeroDivisionError('division by zero')