how to print error in try except python
try:
# some code
except Exception as e:
print("ERROR : "+str(e))
how to print error in try except python
try:
# some code
except Exception as e:
print("ERROR : "+str(e))
python try except
import sys
try:
f = open('myfile.txt')
s = f.readline()
i = int(s.strip())
except OSError as err:
print("OS error: {0}".format(err))
except ValueError:
print("Could not convert data to an integer.")
except:
print("Unexpected error:", sys.exc_info()[0])
raise
python try except
try:
val = 1/0
except Exception as e:
raise Exception('ZeroDivisionError')
try except python
age = input('age:')
try:
new_age = int(age)
except ValueError: # if age is not convertable to int
print('please enter a number...')
try except python
# Python try: except:
try:
print(a + b) # Program will try the add b to a
except:
print("There was an error") # If the program will have an error in the try block
# The except block will run
# except block will run and then the program will continue to run
# Examples:
a = 1
b = 1 # <===== no error, except block skipped
a = 1
b = 'one' # <===== error, except block run
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