print type of exception python
try:
someFunction()
except Exception as ex:
template = "An exception of type {0} occurred. Arguments:\n{1!r}"
message = template.format(type(ex).__name__, ex.args)
print (message)print type of exception python
try:
someFunction()
except Exception as ex:
template = "An exception of type {0} occurred. Arguments:\n{1!r}"
message = template.format(type(ex).__name__, ex.args)
print (message)python try catch
try:
# Dangerous stuff
except ValueError:
# If you use try, at least 1 except block is mandatory!
# Handle it somehow / ignore
except (BadThingError, HorrbileThingError) as e:
# Hande it differently
except:
# This will catch every exception.
else:
# Else block is not mandatory.
# Dangerous stuff ended with no exception
finally:
# Finally block is not mandatory.
# This will ALWAYS happen after the above blocks.try except python
try:
print("I will try to print this line of code")
except ERROR_NAME:
print("I will print this line of code if error ERROR_NAME is encountered")try except python
try:
Age = int(input("Your Age:- "))
except ValueError:
print("Age not in Intger form")python try except
try:
val = 1/0
except Exception as e:
raise Exception('ZeroDivisionError')Copyright © 2021 Codeinu
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