how to print error in try except python
try:
# some code
except Exception as e:
print("ERROR : "+str(e))how to print error in try except python
try:
# some code
except Exception as e:
print("ERROR : "+str(e))try except else finally python
try:
# Some Code....
except:
# optional block
# Handling of exception (if required)
else:
# execute if no exception
finally:
# Some code .....(always executed)python try catch
try:
# Dangerous stuff
except ValueError:
# If you use try, at least 1 except block is mandatory!
# Handle it somehow / ignore
except (BadThingError, HorrbileThingError) as e:
# Hande it differently
except:
# This will catch every exception.
else:
# Else block is not mandatory.
# Dangerous stuff ended with no exception
finally:
# Finally block is not mandatory.
# This will ALWAYS happen after the above blocks.error handling Pyhtin
# taking input from the user
try:
age = int(input("Please enter your age: "))
print(age)
except:
print("please enter a number instead! ")
print('bye')
# if you wanna ask their age until they enter the correct number use While Loop
while True:
try:
age = int(input("Please enter your age: "))
print(age)
except:
print("please enter a number instead! ")
else:
breakpython try else
try:
a=2*3
except TypeError:
print("Exception raised")
else:
print("Everything is ok.")try except python
# Python try: except:
try:
print(a + b) # Program will try the add b to a
except:
print("There was an error") # If the program will have an error in the try block
# The except block will run
# except block will run and then the program will continue to run
# Examples:
a = 1
b = 1 # <===== no error, except block skipped
a = 1
b = 'one' # <===== error, except block runCopyright © 2021 Codeinu
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