how to print error in try except python
try:
# some code
except Exception as e:
print("ERROR : "+str(e))how to print error in try except python
try:
# some code
except Exception as e:
print("ERROR : "+str(e))catch error python
import traceback
dict = {'a':3,'b':5,'c':8}
try:
print(dict[q])
except:
traceback.print_exc()
# This will trace you back to the line where everything went wrong.
# So in this case you will get back line 5catch error data with except python
import sys
try:
S = 1/0 #Create Error
except: # catch *all* exceptions
e = sys.exc_info()
print(e) # (Exception Type, Exception Value, TraceBack)
############
# OR #
############
try:
S = 1/0
except ZeroDivisionError as e:
print(e) # ZeroDivisionError('division by zero')python check for exception
try: # put here the code that you expect to error
# code
except ValueError: # if you want to catch a ValueError
# NOTE: you CANNOT catch a syntax error
# (UNLESS you are trying to execute code from a string with eval())
# code if python caught the exception
except NameError: # you can catch multiple types of errors!
# TIP: you can leave the error type blank to make python catch all types of errors!
# code if another exception is caught (this is pretty much a modified if statement)
else: # if no error has been caught do the following:
# code if no exception has been caughtCopyright © 2021 Codeinu
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