how to print error in try except python
try:
# some code
except Exception as e:
print("ERROR : "+str(e))how to print error in try except python
try:
# some code
except Exception as e:
print("ERROR : "+str(e))catch error data with except python
import sys
try:
S = 1/0 #Create Error
except: # catch *all* exceptions
e = sys.exc_info()
print(e) # (Exception Type, Exception Value, TraceBack)
############
# OR #
############
try:
S = 1/0
except ZeroDivisionError as e:
print(e) # ZeroDivisionError('division by zero')python exception
try:
# code block
except ValueError as ve:
print(ve)return code error python
from turtle import*
from random import randrange
from freegames import square, vector
food = vector(0,0)
snake = [vector(10,0)]
aim = vector(0,-10)
def change(x,y):
aim.x=x
aim.y=y
def inside(head):
return -200<head.x<190 and -200 <head.y <190
def move():
head=snake[-1].copy()
head.move(aim)
if not inside(head) or head in snake:
square(head.x,head.y,9,'red')
update()
a
return
snake.append()
print('snake',len(snake))
if head==food: food.x = randrange(-15,15)*10
food.y = randrange(-15,15)*10
else
snake.pop(0)
clear()
for body in snake:
square(body.x,body.y,9,'green')
square(food.x,food.y,9,'red')
update()
ontime(move, 100)
hideturtle()
tracer(False)
listen()
onkey(lambda:changes(10,0),'right')
onkey(lambda:changes(-10,0),'left')
onkey(lambda:changes(0,10),'up')
onkey(lambda:changes(0,-10),'down')
move()
done()return code error python
File "c:\Users\deoll\Desktop\java\python test\pythontest.py", line 30
else
^
SyntaxError: invalid syntax
PS C:\Users\deoll\Desktop\java>Copyright © 2021 Codeinu
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