how to print error in try except python
try:
# some code
except Exception as e:
print("ERROR : "+str(e))how to print error in try except python
try:
# some code
except Exception as e:
print("ERROR : "+str(e))python try catch
try:
# Dangerous stuff
except ValueError:
# If you use try, at least 1 except block is mandatory!
# Handle it somehow / ignore
except (BadThingError, HorrbileThingError) as e:
# Hande it differently
except:
# This will catch every exception.
else:
# Else block is not mandatory.
# Dangerous stuff ended with no exception
finally:
# Finally block is not mandatory.
# This will ALWAYS happen after the above blocks.catch error data with except python
import sys
try:
S = 1/0 #Create Error
except: # catch *all* exceptions
e = sys.exc_info()
print(e) # (Exception Type, Exception Value, TraceBack)
############
# OR #
############
try:
S = 1/0
except ZeroDivisionError as e:
print(e) # ZeroDivisionError('division by zero')python try except print error
1 (x,y) = (5,0)
2 try:
3 z = x/y
4 except ZeroDivisionError as e:
5 z = e # representation: "<exceptions.ZeroDivisionError instance at 0x817426c>"
6 print z # output: "integer division or modulo by zero"Copyright © 2021 Codeinu
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