Answers for "catch and exception and print it python"

4

print type of exception python

try:
    someFunction()
except Exception as ex:
    template = "An exception of type {0} occurred. Arguments:n{1!r}"
    message = template.format(type(ex).__name__, ex.args)
    print (message)
Posted by: Guest on July-13-2020
0

python file open try except error

def FileCheck(fn):
    try:
      open(fn, "r")
      return 1
    except IOError:
      print "Error: File does not appear to exist."
      return 0

result = FileCheck("testfile")
print result
Posted by: Guest on July-02-2020

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