how to print error in try except python
try:
# some code
except Exception as e:
print("ERROR : "+str(e))how to print error in try except python
try:
# some code
except Exception as e:
print("ERROR : "+str(e))python try catch
try:
# Dangerous stuff
except ValueError:
# If you use try, at least 1 except block is mandatory!
# Handle it somehow / ignore
except (BadThingError, HorrbileThingError) as e:
# Hande it differently
except:
# This will catch every exception.
else:
# Else block is not mandatory.
# Dangerous stuff ended with no exception
finally:
# Finally block is not mandatory.
# This will ALWAYS happen after the above blocks.try except python
try:
print("I will try to print this line of code")
except ERROR_NAME:
print("I will print this line of code if error ERROR_NAME is encountered")python try except
import sys
try:
f = open('myfile.txt')
s = f.readline()
i = int(s.strip())
except OSError as err:
print("OS error: {0}".format(err))
except ValueError:
print("Could not convert data to an integer.")
except:
print("Unexpected error:", sys.exc_info()[0])
raisehow to use except statement in python
>>> def divide(x, y):
... try:
... result = x / y
... except ZeroDivisionError:
... print("division by zero!")
... else:
... print("result is", result)
... finally:
... print("executing finally clause")
...
>>> divide(2, 1)
result is 2.0
executing finally clause
>>> divide(2, 0)
division by zero!
executing finally clause
>>> divide("2", "1")
executing finally clause
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "<stdin>", line 3, in divide
TypeError: unsupported operand type(s) for /: 'str' and 'str'try except python
try:
Age = int(input("Your Age:- "))
except ValueError:
print("Age not in Intger form")Copyright © 2021 Codeinu
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