python sort dictionary alphabetically by key
sortednames=sorted(dictUsers.keys(), key=lambda x:x.lower())
python sort dictionary alphabetically by key
sortednames=sorted(dictUsers.keys(), key=lambda x:x.lower())
sort the dictionary in python
d = {2: 3, 1: 89, 4: 5, 3: 0}
od = sorted(d.items())
print(od)
python sort dictionary by key
In [1]: import collections
In [2]: d = {2:3, 1:89, 4:5, 3:0}
In [3]: od = collections.OrderedDict(sorted(d.items()))
In [4]: od
Out[4]: OrderedDict([(1, 89), (2, 3), (3, 0), (4, 5)])
sort dictionary by values
from collections import OrderedDict
dd = OrderedDict(sorted(d.items(), key=lambda x: x[1]))
print(dd)
how to sort a dictionary
markdict = {"Tom":67, "Tina": 54, "Akbar": 87, "Kane": 43, "Divya":73}
marklist = sorted(markdict.items(), key=lambda x:x[1])
sortdict = dict(marklist)
print(sortdict)
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