check if a number is perfect cube in python
x = int(input())
print(int(round(x ** (1. / 3))) ** 3 == x)check if a number is perfect cube in python
x = int(input())
print(int(round(x ** (1. / 3))) ** 3 == x)how to perform cube in python
# Python Program to Calculate Cube of a Number
number = float(input(" Please Enter any numeric Value : "))
cube = number * number * number
print("The Cube of a Given Number {0} = {1}".format(number, cube))Copyright © 2021 Codeinu
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