Answers for "words.filter(lambda w: len(w)!=0 in w).map(lambda x: (x, 1))"

map function using lambda in python

# Map function 

nums1 = [2,3,5,6,76,4,3,2]
sq = list(map(lambda a : a*a, nums1))
print(sq)

Posted by: Guest on August-07-2020

python3 lambda

>>> sum = lambda x, y : x + y
>>> sum(3,4)
7

Posted by: Guest on April-04-2020

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