map function using lambda in python
# Map function
nums1 = [2,3,5,6,76,4,3,2]
sq = list(map(lambda a : a*a, nums1))
print(sq)map function using lambda in python
# Map function
nums1 = [2,3,5,6,76,4,3,2]
sq = list(map(lambda a : a*a, nums1))
print(sq)reduce function using lambda in python
#Reduce function
from functools import reduce
list2 =[1,2,3,4,5]
fins = reduce(lambda x,y:x+y, list2)
print(fins)
#o/p : 15
# reduce similar to this concept
list2 =[1,2,3,4,5]
adds = 0
for i in list2:
adds+=i
print(adds)map lambda
>>> numbers = [1, 2, 3, 4, 5]
>>> squared = map(lambda num: num ** 2, numbers)
>>> list(squared)
[1, 4, 9, 16, 25]Copyright © 2021 Codeinu
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