python count repeated elements in a list
# Basic syntax:
dict_of_counts = {item:your_list.count(item) for item in your_list}
# Example usage:
your_list = ["a", "b", "a", "c", "c", "a", "c"]
dict_of_counts = {item:your_list.count(item) for item in your_list}
print(dict_of_counts)
--> {'a': 3, 'b': 1, 'c': 3}get all occurrence indices in list python
a_list = [1, 2, 3, 1]
indices = []
for i in range(len(a_list)):
if a_list[i] == 1:
indices.append(i)
# more concise way
a_list = [1, 2, 3, 1]
indices = [index for index, element in enumerate(a_list) if element == 1]how to find no of times a elements in list python
thislist = (1, 3, 7, 8, 7, 5, 4, 6, 8, 5)
x = thislist.count(5)
print(x)python count occurrences of an item in a list
>>> [1, 2, 3, 4, 1, 4, 1].count(1)
3count occurrence in array python
arr = np.array( [1, 2, 3, 2, 1, 2])
occ = np.count_nonzero(arr==0)
print(occ)
0
occ = np.count_nonzero(arr==1)
print(occ)
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