python find index of nth occurrence in list
# Basic syntax using list comprehension: [i for i, n in enumerate(your_list) if n == condition][match_number] # Where: # - This setup makes a list of the indexes for list items that meet # the condition and then match_number returns the nth index # - enumerate() returns iterates through your_list and returns each # element (n) and index value (i) # Example usage: your_list = ['w', 'e', 's', 's', 's', 'z','z', 's'] [i for i, n in enumerate(your_list) if n == 's'][0] --> 2 # 2 is returned because it is the index of the first element that # meets the condition (being 's')
