python find index of nth occurrence in list
# Basic syntax using list comprehension:
[i for i, n in enumerate(your_list) if n == condition][match_number]
# Where:
# - This setup makes a list of the indexes for list items that meet
# the condition and then match_number returns the nth index
# - enumerate() returns iterates through your_list and returns each
# element (n) and index value (i)
# Example usage:
your_list = ['w', 'e', 's', 's', 's', 'z','z', 's']
[i for i, n in enumerate(your_list) if n == 's'][0]
--> 2
# 2 is returned because it is the index of the first element that
# meets the condition (being 's')