python count repeated elements in a list
# Basic syntax:
dict_of_counts = {item:your_list.count(item) for item in your_list}
# Example usage:
your_list = ["a", "b", "a", "c", "c", "a", "c"]
dict_of_counts = {item:your_list.count(item) for item in your_list}
print(dict_of_counts)
--> {'a': 3, 'b': 1, 'c': 3}count similar values in list python
MyList = ["a", "b", "a", "c", "c", "a", "c"]
return my_dict = {i:MyList.count(i) for i in MyList}
# returns :
{'a': 3, 'c': 3, 'b': 1}
# OR
from collections import Counter
return my_dict = dict(Counter(MyList))
# returns :
{'a': 3, 'c': 3, 'b': 1}
# the both returns the same so it's up to you to choose the one you prefere ;)count the duplicates in a list in python
some_list=['a','b','c','b','d','m','n','n']
my_list=sorted(some_list)
duplicates=[]
for i in my_list:
if my_list.count(i)>1:
if i not in duplicates:
duplicates.append(i)
print(duplicates)python find number of occurrences in list
student_grades = [9.1, 8.8, 10.0, 7.7, 6.8, 8.0, 10.0, 8.1, 10.0, 9.9]
samebnumber = student_grades.count(10.0)
print(samebnumber)Copyright © 2021 Codeinu
Forgot your account's password or having trouble logging into your Account? Don't worry, we'll help you to get back your account. Enter your email address and we'll send you a recovery link to reset your password. If you are experiencing problems resetting your password contact us
