python count repeated elements in a list
# Basic syntax:
dict_of_counts = {item:your_list.count(item) for item in your_list}
# Example usage:
your_list = ["a", "b", "a", "c", "c", "a", "c"]
dict_of_counts = {item:your_list.count(item) for item in your_list}
print(dict_of_counts)
--> {'a': 3, 'b': 1, 'c': 3}count similar values in list python
MyList = ["a", "b", "a", "c", "c", "a", "c"]
return my_dict = {i:MyList.count(i) for i in MyList}
# returns :
{'a': 3, 'c': 3, 'b': 1}
# OR
from collections import Counter
return my_dict = dict(Counter(MyList))
# returns :
{'a': 3, 'c': 3, 'b': 1}
# the both returns the same so it's up to you to choose the one you prefere ;)count the duplicates in a list in python
some_list=['a','b','c','b','d','m','n','n']
my_list=sorted(some_list)
duplicates=[]
for i in my_list:
if my_list.count(i)>1:
if i not in duplicates:
duplicates.append(i)
print(duplicates)how to find duplicate numbers in list in python
l=[1,2,3,4,5,2,3,4,7,9,5]
l1=[]
for i in l:
if i not in l1:
l1.append(i)
else:
print(i,end=' ')Copyright © 2021 Codeinu
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