binary number in python 32 bit
>>> '{:032b}'.format(100)
'00000000000000000000000001100100'
>>> '{:032b}'.format(8589934591)
'111111111111111111111111111111111'
>>> '{:032b}'.format(8589934591 + 1)
'1000000000000000000000000000000000' # N.B. this is 33 digits longpython int binary
print('{0:b}'.format(3)) # '11'
print('{0:8b}'.format(3)) # ' 11'
print('{0:08b}'.format(3)) # '00000011'
def int2bin(integer, digits):
if integer >= 0:
return bin(integer)[2:].zfill(digits)
else:
return bin(2**digits + integer)[2:]
print(int2bin(3, 6)) # '000011'Copyright © 2021 Codeinu
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