setwd python
os.chdir("/home/varun/temp")setwd python
os.chdir("/home/varun/temp")sets in python
The simplest way to create set is:
1. from list
code:
s = [1,2,3]
set = set(s)
print(set)
2. s,add() method
code:
set.add(1)
set.add(2)
set.remove(2)
print(set) // 1
3. Set conatins unique elementspython set
# A set contains unique elements of which the order is not important
s = set()
s.add(1)
s.add(2)
s.remove(1)
print(s)
# Can also be created from a list (or some other data structures)
num_list = [1,2,3]
set_from_list = set(num_list)python dictionary value as set
word_dict = dict()
word_dict["foo"] = set()
word_dict["foo"].add("baz")
word_dict["foo"].add("bang")sets in python
basket = {'apple', 'orange', 'apple', 'pear', 'orange', 'banana'}
print(basket) # show that duplicates have been removed
# OUTPUT {'orange', 'banana', 'pear', 'apple'}
print('orange' in basket) # fast membership testing
# OUTPUT True
print('crabgrass' in basket)
# OUTPUT False
# Demonstrate set operations on unique letters from two words
print(a = set('abracadabra'))
print(b = set('alacazam'))
print(a) # unique letters in a
# OUTPUT {'a', 'r', 'b', 'c', 'd'}
print(a - b) # letters in a but not in b
# OUTPUT {'r', 'd', 'b'}
print(a | b) # letters in a or b or both
# OUTPUT {'a', 'c', 'r', 'd', 'b', 'm', 'z', 'l'}
print(a & b) # letters in both a and b
# OUTPUT {'a', 'c'}
print(a ^ b) # letters in a or b but not both
# OUTPUT {'r', 'd', 'b', 'm', 'z', 'l'}sets in python
set_of_base10_numbers = {1, 2, 3, 4, 5, 6, 7, 8, 9, 0}
set_of_base2_numbers = {1, 0}
intersection = set_of_base10_numbers.intersection(set_of_base2_numbers)
union = set_of_base10_numbers.union(set_of_base2_numbers)
'''
intersection: {0, 1}:
if the number is contained in both sets it becomes part of the intersection
union: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9}:
if the number exists in at lease one of the sets it becomes part of the union
'''Copyright © 2021 Codeinu
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