python zip extract directory
import zipfile
archive = zipfile.ZipFile('archive.zip')
for file in archive.namelist():
if file.startswith('foo/'):
archive.extract(file, 'destination_path')python zip extract directory
import zipfile
archive = zipfile.ZipFile('archive.zip')
for file in archive.namelist():
if file.startswith('foo/'):
archive.extract(file, 'destination_path')zip a directory in python
shutil.make_archive(output_filename, 'zip', dir_name)Copyright © 2021 Codeinu
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