how to sum digits of a number in python
number = 123 # the number you want summed up
sum_of_digits = 0
for digit in str(number):
sum_of_digits += int(digit)
print(sum_of_digits) # printing the final sum of numberhow to sum digits of a number in python
number = 123 # the number you want summed up
sum_of_digits = 0
for digit in str(number):
sum_of_digits += int(digit)
print(sum_of_digits) # printing the final sum of numberpython sum of digits
def sum_digits(n):
s = 0
while n:
s += n % 10
n //= 10
return ssum of digits in a number python
digit_sum = lambda s: sum(int(digit) for digit in str(s)) #without recursion
#sum of digits using recursion
dsum = 0 # we define dsum outside of the function so its value isn't reset every time the function gets called recursivley
def rdigit_sum(s):
global dsum # making dsum 'global' allows us to use it a function
if s: # checks if s has digits to add to dsum
dsum += s%10 # adds the current units digit to dsum
s = s//10 # removes the current units digit
else: # if there are no digits left
s = dsum # this block reassigns s to dsum, then resets dsum to 0 so dsum doesn't already have a value if this function is called more than once in a program
dsum = 0
return s
return rdigit_sum(s) # this is the 'recursive' part of the program that calls the function againsum of digits in a string
String -- sum of digits in a string
Write a method that can return the sum of the digits in a string
public static int sumOfDigits(String s) {
int total = 0;
char[] ch = s.toCharArray();
for(char each: ch) {
if(Character.isDigit(each)) {
total += Integer.valueOf(""+each);
}
}
return total;
}Copyright © 2021 Codeinu
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