pyhton permutations
# A Python program to print all permutations using library function
from itertools import permutations
perm = permutations([1, 2, 3])
for i in list(perm):
print (i)
# (1, 2, 3)
# (1, 3, 2)
# (2, 1, 3)
# (2, 3, 1)
# (3, 1, 2)
# (3, 2, 1)all permutations python
import itertools
print(list(itertools.permutations([1,2,3])))how to get all permutations of an array
/* to be used something like this:
int [] toBePermuted = new int [] {1, 2, 3, 4};
ArrayList<int[]> a = heap(toBePermuted);
any mention of int [] can be replaced with any other Array of objects */
ArrayList<int []> heap(int [] input) {
ArrayList<int []> ret = new ArrayList<int []> ();
ret = generate(input.length, input, ret);
return ret;
}
ArrayList<int []> generate(int k, int [] a, ArrayList<int []> output) {
if (k == 1) {
output.add(a.clone());
} else {
output = generate(k-1, a, output);
for (int i=0; i<k-1; i++) {
if (k%2 == 0) {
int temp = a[i];
a[i] = a[k-1];
a[k-1] = temp;
} else {
int temp = a[0];
a[0] = a[k-1];
a[k-1] = temp;
}
generate(k-1, a, output);
}
}
return output;
}how to print all permutations of a string
void permutation(string s)
{
sort(s.begin(),s.end());
do{
cout << s << " ";
}
while(next_permutation(s.begin(),s.end()); // std::next_permutation
cout << endl;
}Copyright © 2021 Codeinu
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