pyhton permutations
# A Python program to print all permutations using library function
from itertools import permutations
perm = permutations([1, 2, 3])
for i in list(perm):
print (i)
# (1, 2, 3)
# (1, 3, 2)
# (2, 1, 3)
# (2, 3, 1)
# (3, 1, 2)
# (3, 2, 1)all permutations python
import itertools
print(list(itertools.permutations([1,2,3])))python all permutations of a string
>>> from itertools import permutations
>>> perms = [''.join(p) for p in permutations('stack')]
>>> permsfind all permutations of a string
void permute(string a, int l, int r)
{
// Base case
if (l == r)
cout<<a<<endl;
else
{
// Permutations made
for (int i = l; i <= r; i++)
{
// Swapping done
swap(a[l], a[i]);
// Recursion called
permute(a, l+1, r);
//backtrack
swap(a[l], a[i]);
}
}
}generate all permutations of string
void perm(char a[], int level){
static int flag[10] = {0};
static char res[10];
// If we are the last character of the input string
if(a[level] == ' '){
// First we assign stopping point to result
res[level] = ' ';
// Now we print everything
for(int i = 0; res[i] != ' '; ++i){
printf("%c", res[i]);
}
printf("n");
++counter;
}
else{
// Scan the original string and flag to see what letters are available
for(int i = 0; a[i] != ' '; ++i){
if(flag[i] == 0){
res[level] = a[i];
flag[i] = 1;
perm(a, level + 1);
flag[i] = 0;
}
}
}
}
int main(){
char first[] = "abc";
perm(first, 0);
return 0;
}how to print all permutations of a string
void permutation(string s)
{
sort(s.begin(),s.end());
do{
cout << s << " ";
}
while(next_permutation(s.begin(),s.end()); // std::next_permutation
cout << endl;
}Copyright © 2021 Codeinu
Forgot your account's password or having trouble logging into your Account? Don't worry, we'll help you to get back your account. Enter your email address and we'll send you a recovery link to reset your password. If you are experiencing problems resetting your password contact us
