quadratic equation solver python
# Solve the quadratic equation ax**2 + bx + c = 0
# import complex math module
import cmath
a = 1
b = 5
c = 6
# calculate the discriminant
d = (b**2) - (4*a*c)
# find two solutions
sol1 = (-b-cmath.sqrt(d))/(2*a)
sol2 = (-b+cmath.sqrt(d))/(2*a)
print('The solution are {0} and {1}'.format(sol1,sol2))quadratic equation plot in python
import matplotlib.pyplot as plt
import numpy as np
# 100 linearly spaced numbers
x = np.linspace(0,1,10)
eta1=0.05
eta2=0.1
lmd1= 2.8
# the function, which is y = x^2 here
y = 0.5*(-(1/3)*eta1*x**2 + np.sqrt( ((1/3)*eta1*x**2)**2-4*(3*x**2*2.8**2-1))
# setting the axes at the centre
fig = plt.figure()
ax = fig.add_subplot(1, 1, 1)
ax.spines['left'].set_position('center')
ax.spines['bottom'].set_position('zero')
ax.spines['right'].set_color('none')
ax.spines['top'].set_color('none')
ax.xaxis.set_ticks_position('bottom')
ax.yaxis.set_ticks_position('left')
# plot the function
plt.plot(x,y, 'r')
# show the plot
plt.show()Copyright © 2021 Codeinu
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