quadratic equation solver python
# Solve the quadratic equation ax**2 + bx + c = 0
# import complex math module
import cmath
a = 1
b = 5
c = 6
# calculate the discriminant
d = (b**2) - (4*a*c)
# find two solutions
sol1 = (-b-cmath.sqrt(d))/(2*a)
sol2 = (-b+cmath.sqrt(d))/(2*a)
print('The solution are {0} and {1}'.format(sol1,sol2))Python Program to Solve Quadratic Equation
roots = ( -b + sqrt(b ^ 2 - 4 * a *c) ) / (2 * a) , ( -b - sqrt(b ^ 2 - 4 * a *c) ) / (2 * a)quadratic equations in python
def square(n):
num=n
newnum=n*n
return newnumCopyright © 2021 Codeinu
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