pass argument to a py file
import sys
def hello(a,b):
print "hello and that's your sum:", a + b
if __name__ == "__main__":
a = int(sys.argv[1])
b = int(sys.argv[2])
hello(a, b)
# If you type : py main.py 1 5
# It should give you "hello and that's your sum:6"read argument from terminal
#!/usr/bin/python
import sys
print 'Number of arguments:', len(sys.argv), 'arguments.'
print 'Argument List:', str(sys.argv)
#Terminal
# $ python test.py arg1 arg2 arg3
#print
#Number of arguments: 4 arguments.
#Argument List: ['test.py', 'arg1', 'arg2', 'arg3']python get args
import sys
print(sys.argv)args in python
# if args is not passed it return message
# "Hey you didn't pass the arguements"
def ech(nums,*args):
if args:
return [i ** nums for i in args] # list comprehension
else:
return "Hey you didn't pass args"
print(ech(3,4,3,2,1))args in python
def func2(*args):
for i in args:
print(i * 2)
func2(2,3,4,5)args in python
# if option is not passed it still returns 20
# if option = True or option = 1 is passed it returns 20 which is sum of numbers
# if option = False or option = 0 is passed it returns 0
def addition(a, b, *args, option=True):
result = 0
if option:
for i in args:
result += i
return a + b + result
else:
return resultCopyright © 2021 Codeinu
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