python vernam cipher
vernam_dict = dict((i, chr(i + 96)) for i in range(1, 27))
# Vernam by replacing char of plain by char(ord(sum of plain and key))
def vernam_encrypt(plain, key):
plain = plain.lower()
ckey = ''.join([(key[i % len(key)]) for i in range(len(list(plain)))])
print(ckey)
cipher = ''
for i in range(len(plain)):
if plain[i] == ' ':
cipher += ' '
else:
cipher += vernam_dict[(ord(plain[i]) + ord(ckey[i])) % 26]
print(cipher, plain)
print(vernam_encrypt('mountains are bae', 'hello'))
def vernam_decrypt(ctext, key):
cupper = ctext.upper()
text_num = [letters.index(u) for u in cupper]
intm_key = [letters.index(ik) for ik in key]
c = ''
for i in range(len(cupper)):
ee = text_num[i] - intm_key[i]
if ee < 0:
c += letters[ee + 26]
else:
c += letters[ee]
return c
print(vernam_decrypt('BSJDE', 'UOYSQ'))