how to check if a number is odd python
num = int(input("Enter a number: "))
if (num % 2) == 0:
print("{0} is Even number".format(num))
else:
print("{0} is Odd number".format(num)) how to check if a number is odd python
num = int(input("Enter a number: "))
if (num % 2) == 0:
print("{0} is Even number".format(num))
else:
print("{0} is Odd number".format(num)) how to detect an even number in python
mynumber = int(input("Enter number")) # Ask an integer number to the user
if mynumber % 2 == 0: # % = modelo, It is equal to the rest of the division
print(mynumber, "is an even number")
else: # The rest of 7 / 2 is 2.5, not 0
print(mynumber, "is an odd number")python even or odd
injd = int(input('Enter a number'))
n = injd % 2
if n > 0:
print('This is an odd number')
else:
print('This is an even number')Copyright © 2021 Codeinu
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