odd or even python
# Python program to check if the input number is odd or even.
# A number is even if division by 2 gives a remainder of 0.
# If the remainder is 1, it is an odd number.
num = int(input("Enter a number: "))
if (num % 2) == 0:
print("{0} is Even".format(num))
else:
print("{0} is Odd".format(num))program to find even numbers in python
m = int(input("Enter number"))
if m % 2 == 0:
print(m,"is an even number")
else:
print(m,"is an odd number")how to check if a number is odd python
num = int(input("Enter a number: "))
if (num % 2) == 0:
print("{0} is Even number".format(num))
else:
print("{0} is Odd number".format(num)) python 3 numbers of a range is even
lst = []
for i in range(1000,3001):
flag = 1
for j in str(i): # every integer number i is converted into string
if ord(j)%2 != 0: # ord returns ASCII value and j is every digit of i
flag = 0 # flag becomes zero if any odd digit found
if flag == 1:
lst.append(str(i)) # i is stored in list as string
print(",".join(lst))finding odd even python
number = int(input("Write a number:- "))
if number%2 == 0:
print("Even number")
else:
print("odd number")how to detect an even number in python
mynumber = int(input("Enter number")) # Ask an integer number to the user
if mynumber % 2 == 0: # % = modelo, It is equal to the rest of the division
print(mynumber, "is an even number")
else: # The rest of 7 / 2 is 2.5, not 0
print(mynumber, "is an odd number")Copyright © 2021 Codeinu
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