pandas timedelta to seconds
df['column_with_timedelta'].dt.total_seconds()pandas timedelta to seconds
df['column_with_timedelta'].dt.total_seconds()converting pandas._libs.tslibs.timedeltas.Timedelta to days
# Convert TimeDelta column (5 days etc.) into an integer column (5)
import numpy as np
df.timeDelta = (df.timeDelta / np.timedelta64(1,'D')).astype(int)timedelta64 total_mins
import datetime
def minutes(date_time_older, date_time_newer):
date_time_difference = round((date_time_newer-date_time_older).total_seconds()/60)
return date_time_differenceCopyright © 2021 Codeinu
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