pandas timedelta to seconds
df['column_with_timedelta'].dt.total_seconds()pandas timedelta to seconds
df['column_with_timedelta'].dt.total_seconds()python timedelta
from datetime import timedelta
# Create a delta time
datetime_delta = timedelta(weeks = 1, days = 2, hours = 4, minutes = 10,
seconds = 8, milliseconds = 25, microseconds = 8)
print("Delta datetime :- ", datetime_delta)
>>> Delta datetime :- 9 days, 4:10:08.025008converting pandas._libs.tslibs.timedeltas.Timedelta to days
# Convert TimeDelta column (5 days etc.) into an integer column (5)
import numpy as np
df.timeDelta = (df.timeDelta / np.timedelta64(1,'D')).astype(int)pd.timedelta
# convert the entire timedelta to seconds
# this is the same as td / timedelta(seconds=1)
(df.from_date - df.to_date).dt.total_seconds()
[out]:
0 211089.82
1 13264.30
2 31373.76
dtype: float64
# get the number of days
(df.from_date - df.to_date).dt.days
[out]:
0 2
1 0
2 0
dtype: int64
# get the seconds for hours + minutes + seconds, but not days
# note the difference from total_seconds
(df.from_date - df.to_date).dt.seconds
[out]:
0 38289
1 13264
2 31373
dtype: int64Copyright © 2021 Codeinu
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