is there find_all method in re or regex module in python?
>>> text = "He was carefully disguised but captured quickly by police."
>>> re.findall(r"w+ly", text)
['carefully', 'quickly']
is there find_all method in re or regex module in python?
>>> text = "He was carefully disguised but captured quickly by police."
>>> re.findall(r"w+ly", text)
['carefully', 'quickly']
regex findall
import re
# regex for finding mentions in a tweet
regex = r"(?<!RTs)@S+"
tweet = '@tony I am so over @got and @sarah is dead to me.'
# mentions = ['@tony', '@got', '@sarah']
mentions = re.findall(regex, tweet)
python .findall
## Search for pattern 'bb' in string 'aabbcc'.
## All of the pattern must match, but it may appear anywhere.
## On success, match.group() is matched text.
match = re.search(r'bb', 'aabbcc') # found, match.group() == "bb"
match = re.search(r'cd', 'aabbcc') # not found, match == None
## . = any char but n
match = re.search(r'...c', 'aabbcc') # found, match.group() == "abbc"
## d = digit char, w = word char
match = re.search(r'ddd', 'p123g') # found, match.group() == "123"
match = re.search(r'www', '@@abcd!!') # found, match.group() == "abc"
python re
m = re.search(r'[cbm]at', 'aat')
print(m)
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