is there find_all method in re or regex module in python?
>>> text = "He was carefully disguised but captured quickly by police."
>>> re.findall(r"w+ly", text)
['carefully', 'quickly']is there find_all method in re or regex module in python?
>>> text = "He was carefully disguised but captured quickly by police."
>>> re.findall(r"w+ly", text)
['carefully', 'quickly']regex findall
import re
# regex for finding mentions in a tweet
regex = r"(?<!RTs)@S+"
tweet = '@tony I am so over @got and @sarah is dead to me.'
# mentions = ['@tony', '@got', '@sarah']
mentions = re.findall(regex, tweet)re python3
import re
>>> m = re.search('(?<=abc)def', 'abcdef')
>>> m.group(0)
'def'python .findall
## Search for pattern 'bb' in string 'aabbcc'.
## All of the pattern must match, but it may appear anywhere.
## On success, match.group() is matched text.
match = re.search(r'bb', 'aabbcc') # found, match.group() == "bb"
match = re.search(r'cd', 'aabbcc') # not found, match == None
## . = any char but n
match = re.search(r'...c', 'aabbcc') # found, match.group() == "abbc"
## d = digit char, w = word char
match = re.search(r'ddd', 'p123g') # found, match.group() == "123"
match = re.search(r'www', '@@abcd!!') # found, match.group() == "abc"python re
if pattern := re.search("[iI] am (.*)", "I am tired"):
print(f"Hi {pattern.group(1)}, I'm dad!")Copyright © 2021 Codeinu
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