python find index by value
>>> ["foo", "bar", "baz"].index("bar")
1
python find index by value
>>> ["foo", "bar", "baz"].index("bar")
1
python find index of first matching element in a list
# Basic syntax:
list.index(element, start, end)
# Where:
# - Element is the item you're looking for in the list
# - Start is optional, and is the list index you want to start at
# - End is option, and is the list index you want to stop searching at
# Note, Python is 0-indexed
# Example usage:
my_list = [1, 2, 3, 4, 5, 6, 7, 8, 42, 9, 10]
my_list.index(42)
--> 8
python index method
my_string = "Hello World!"
my_string.index("l") # outputs 2
# this method only outputs the index of the first "l" value in the string/list
how to find index of list of list in python
[(i, colour.index(c))
for i, colour in enumerate(colours)
if c in colour]
how to index lists in python
# Make the list
list = ['bananas', 'apples', 'watermellon']
# Print the word apples from the list
print(list[1])
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