python sort list in reverse
#1 Changes list
list.sort(reverse=True)
#2 Returns sorted list
sorted(list, reverse=True)
python sort list in reverse
#1 Changes list
list.sort(reverse=True)
#2 Returns sorted list
sorted(list, reverse=True)
how do i sort list in python
my_list = [9, 3, 1, 5, 88, 22, 99]
# sort in decreasing order
my_list = sorted(my_list, reverse=True)
print(my_list)
# sort in increasing order
my_list = sorted(my_list, reverse=False)
print(my_list)
# another way to sort using built-in methods
my_list.sort(reverse=True)
print(my_list)
# sort again using slice indexes
print(my_list[::-1])
# Output
# [99, 88, 22, 9, 5, 3, 1]
# [1, 3, 5, 9, 22, 88, 99]
# [99, 88, 22, 9, 5, 3, 1]
# [1, 3, 5, 9, 22, 88, 99]
pythonn sort example
gList = [ "Rocket League", "Valorant", "Grand Theft Autu 5"]
gList.sort()
# OUTPUT --> ['Grand Theft Auto 5', 'Rocket League', 'Valorant']
# It sorts the list according to their names
python sort
>>> student_tuples = [
... ('john', 'A', 15),
... ('jane', 'B', 12),
... ('dave', 'B', 10),
... ]
>>> sorted(student_tuples, key=lambda student: student[2]) # sort by age
[('dave', 'B', 10), ('jane', 'B', 12), ('john', 'A', 15)]
sort list python
>>> a = [5, 2, 3, 1, 4]
>>> a.sort()
>>> a
[1, 2, 3, 4, 5]
sort python
>>> x = [1 ,11, 2, 3]
>>> y = sorted(x)
>>> x
[1, 11, 2, 3]
>>> y
[1, 2, 3, 11]
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