Answers for "array sort method"

25

JS array sort

numArray.sort((a, b) => a - b); // For ascending sort
numArray.sort((a, b) => b - a); // For descending sort
Posted by: Guest on May-08-2021
13

javascript sort

var names = ["Peter", "Emma", "Jack", "Mia", "Eric"];
names.sort(); // ["Emma", "Eric", "Jack", "Mia", "Peter"]

var objs = [
  {name: "Peter", age: 35},
  {name: "Emma", age: 21},
  {name: "Jack", age: 53}
];

objs.sort(function(a, b) {
  return a.age - b.age;
}); // Sort by age (lowest first)
Posted by: Guest on May-21-2020
3

javascript sort object

var maxSpeed = {
    car: 300, 
    bike: 60, 
    motorbike: 200, 
    airplane: 1000,
    helicopter: 400, 
    rocket: 28800
};
var sortable = [];
for (var vehicle in maxSpeed) {
    sortable.push([vehicle, maxSpeed[vehicle]]);
}

sortable.sort(function(a, b) {
    return a[1] - b[1];
});

//[["bike", 60], ["motorbike", 200], ["car", 300],
//["helicopter", 400], ["airplane", 1000], ["rocket", 28800]]
Posted by: Guest on April-19-2020
1

array sort js

arr = ['width', 'score', done', 'neither' ]
arr.sort() // results to ["done", "neither", "score", "width"]

arr.sort((a,b) => a.localeCompare(b)) 
// if a-b (based on their unicode values) produces a negative value, 
// a comes before b, the reverse if positive, and as is if zero

//When you sort an array with .sort(), it assumes that you are sorting strings
//. When sorting numbers, the default behavior will not sort them properly.
arr = [21, 7, 5.6, 102, 79]
arr.sort((a, b) => a - b) // results to [5.6, 7, 21, 79, 102]
// b - a will give you the reverse order of the sorted items 

//this explnation in not mine
Posted by: Guest on October-07-2020
7

javascript sort

homes.sort(function(a, b) {
    return parseFloat(a.price) - parseFloat(b.price);
});
Posted by: Guest on March-17-2020
4

how the sort function works javascript

const unsorted = ['d', 'd', 'h', 'r', 'v', 'z', 'f', 'c', 'g'];
const sorted = unsorted.sort();

console.log(sorted);
//["c", "d", "d", "f", "g", "h", "r", "v", "z"]


const unsortedNums = [45, 56, 3, 3, 4, 6, 7, 45, 1];
const sortedNums = unsortedNums.sort((a, b) => {
	return a - b;
});

console.log(sortedNums);
//[1, 3, 3, 4, 6, 7, 45, 45, 56]
Posted by: Guest on April-07-2020

Browse Popular Code Answers by Language