Answers for "timedelta 6 years"

datetime.timedelta months

from datetime import timedelta
from dateutil.relativedelta import relativedelta

end_date = start_date + relativedelta(months=delta_period) + timedelta(days=-delta_period)

python strftime iso 8601

>>> # convert string in iso 8601 date dime format to python datetime type
>>> import datetime
>>> datetime.datetime.strptime('2020-06-19T15:52:50Z', "%Y-%m-%dT%H:%M:%SZ")
datetime.datetime(2020, 6, 19, 15, 52, 50)