fizzbuzz python
def fizz_buzz(num):
if num % 3 == 0 and num % 5 == 0:
return "fizzBuzz"
elif num % 3 == 0:
return "fizz"
elif num % 5 == 0:
return "buzz"
else:
return numfizzbuzz python
def fizz_buzz(num):
if num % 3 == 0 and num % 5 == 0:
return "fizzBuzz"
elif num % 3 == 0:
return "fizz"
elif num % 5 == 0:
return "buzz"
else:
return numfizzbuzz python solution
for number in range(1, 101):
if number % 3 == 0 and number % 5 == 0:
print("FizzBuzz")
if number % 3 == 0:
print("Fizz")
if number % 5 == 0:
print("Buzz")
else:
print([number])Copyright © 2021 Codeinu
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