making your own range function with step in python
def range_with_step(start_num,end_num,step_num):
sequence2 = [start_num]
while start_num < end_num:
start_num += step_num
sequence2.append(start_num)
return sequence2
print(range_with_step(0,6,3))python range
# range(start, stop, step)
# start = (can be ommitted) index to begin at (INCLUSIVE)
# stop = generate numbers up to, but not including this number (EXCLUSIVE)
# step = (can be omitted) difference between each number in the sequence
# idx: 0 1 2 3 4
# arr: 19 5 3 22 13
arr = [19,5,3,22,13]
# range(stop)
for i in range(len(arr)):
print(arr[i]) # prints: 19, 5, 3, 22, 13
# range(start, stop)
for i in range(2, len(arr)):
print(arr[i]) # prints: 3, 22, 13
# range(start, stop, step)
for i in range(0, len(arr), 2):
print(arr[i]) # prints: 19, 3, 13
# reverse:
for i in range(len(arr)-1, -1, -1):
print(arr[i])range in python
#range(start,stop,step)
for x in range(0,20,2):
print(x)range parameters python
arr_data=[1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20]
user = int(input("Enter the product of numbers: "))
for i in range(0,20,1):
a = arr_data[i]
for t in range(0,20,1):
b = arr_data[t]
if (a*b) == user:
print(a,"x",b,"=",user)
else:
passrange() python
#can be used a sequence of numbers
x = range(6)
print(x)
#Outputs 0 1 2 3 4 5
for i in range(start,finish ,step)
#gives range of numbers
#start is optional default is 0
#finish needed specifying when to stop
#step is incremetntaition of jump also optionalrange(n,n) python
# if numbers are same in the range function then,
# the range function outputs empty range
# this is because, there are no integers b/w n and n
for i in range(1,1):
print("runs")
# prints nothingCopyright © 2021 Codeinu
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