making your own range function with step in python
def range_with_step(start_num,end_num,step_num):
sequence2 = [start_num]
while start_num < end_num:
start_num += step_num
sequence2.append(start_num)
return sequence2
print(range_with_step(0,6,3))python range in intervals of 10
print("using start, stop, and step arguments in Python range() function")
print("Printing All odd numbers between 1 and 10 using range()")
for i in range(1, 10, 2):
print(i, end=', ')python range
# range(start, stop, step)
# start = (can be ommitted) index to begin at (INCLUSIVE)
# stop = generate numbers up to, but not including this number (EXCLUSIVE)
# step = (can be omitted) difference between each number in the sequence
# idx: 0 1 2 3 4
# arr: 19 5 3 22 13
arr = [19,5,3,22,13]
# range(stop)
for i in range(len(arr)):
print(arr[i]) # prints: 19, 5, 3, 22, 13
# range(start, stop)
for i in range(2, len(arr)):
print(arr[i]) # prints: 3, 22, 13
# range(start, stop, step)
for i in range(0, len(arr), 2):
print(arr[i]) # prints: 19, 3, 13
# reverse:
for i in range(len(arr)-1, -1, -1):
print(arr[i])range parameters python
arr_data=[1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20]
user = int(input("Enter the product of numbers: "))
for i in range(0,20,1):
a = arr_data[i]
for t in range(0,20,1):
b = arr_data[t]
if (a*b) == user:
print(a,"x",b,"=",user)
else:
passrange in python
for i in range (start, step, stop):
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