Answers for "leap year solution"

5

leap year algorithm

def isLeapYear (year):
    if ((year % 4 == 0) and (year % 100 != 0)) or (year % 400 == 0):
		true
    else:
    	false
Posted by: Guest on February-18-2021
-1

leap year

import calendar

def is_leap(year):
    return calendar.isleap(year)
Posted by: Guest on May-06-2021

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